//uva12149 #include <iostream> using namespace std; int ans1(int n) { return n * (n + 1) * (2 * n + 1) / 6; } int ans2(int n) { int sum = 0; for (int i = 1; i <= n; i++) sum += i * i; return sum; } int main() { int n; while (cin >> n) { if (n == 0) break; cout << ans2(n) << endl; } return 0; }